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If the specific heat of alu- minimum is 900 j/kg x c, how much energy is needed to raise the temperature of a 3 kg sample from 35c to 45c?

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hbj

Answer:

27000 J

Step-by-step explanation:

The specific heat equation is: Q = mC∆T

Q is the energy in Joules.

m is the mass in grams of the substance.

C is the specific heat capacity.

∆T is the change in temperature.

Let's plug in what we know.

  • The specific heat of aluminum is 900 j/kg ºC
  1. Let's convert j/kg to j/g by dividing by 1000.
  2. The specific heat capacity is 0.9 j/gºC
  • We have 3 kg of aluminum.
  1. Let's convert kg to g by multiplying by 1000.
  2. We have 3000 g of aluminum.
  • The temperature is being raised from 35ºC to 45ºC, which is 10ºC

Q = 3000(0.9)(10)

Q = 27000 J

Hope this helps!

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