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Hello ! Pls help, i'm really confused T-T 29.0 grams of H2CO3 are dissolved in enough water to make 700.0 mL of solution. A. 0.468 L B. 0.468 moles/liter C. 62.02 g/mole D. 0.668 L E. 0.668 M

Respuesta :

Answer:

Explanation:

Molecular weight of H₂CO₃ = 2 + 12 + 48 = 62

29 g of H₂CO₃ = 29 / 62 moles

= .4677 moles

.4677 moles are dissolved in .7 L

molarity of solution = .4677 / .7

= .668 M .

So solution formed is .668 M .

Option E is correct .

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