Respuesta :
Answer:
The amount of energy that would be burnt in climbing stairs all day is approximately 52,738,560 Joules
Explanation:
The question is with regards to an experiment with details that can be obtained from the U Oregon website
The given parameters of the question are;
The energy consumed by a human each day = 2,500 kcal = 10,450,000 J
The required parameters obtained from U Oregon website are;
The average weight of a student, W ≈ 60 kg × 9.81 m/s² = 588.6 N
The average time it takes a student to run up a flight of stairs = 5.4 s
The height of the stairs, h = 0.2 m × 28 = 5.6 meters
Therefore, we get;
Work done in climbing up the stares = W × h = 588.6 N × 5.6 meters = 3,296.16 J
The height the student can climb in a day is given as follows;
The time of 1 day in seconds, t = 86,400 s
The height the student climbs in 5.4 s = 5.6 m
∴ Vertical velocity, [tex]v_y[/tex] = 5.6 m/(5.4 s) = (28/27) m/s
The vertical height the student climbs in a day, [tex]h_{(v \, all \, day)}[/tex] = [tex]v_y[/tex] × t
∴ [tex]h_{(v \, all \, day)}[/tex] = (28/27) m/s × 86,400 = 89,600 m
The work done all day = W × [tex]h_{(v \, all \, day)}[/tex] = 588.6 N × 89,600 m = 52,738,560 J
The amount of energy in joules that would be burnt in climbing stairs all day = The work done all day = 52,738,560 Joules
