Answer: 10. The reactant in Reaction B is [tex]H_{2}O_{2}[/tex].
11. The products in Reaction B are [tex]H_{2}O[/tex] and [tex]O_{2}[/tex].
12. There are 2 molecules present on the reactant side of the equation.
13. There are 3 molecules present on the product side of the equation.
Explanation:
The given reaction equation is as follows.
[tex]Reaction B: 2H_{2}O_{2}(aq) \rightarrow 2H_{2}O(l) + O_{2}(g)[/tex]
Reactants are the species present on the left side of a chemical equation.
Products are the species present on the right side of a chemical equation.
Therefore, the reactant in Reaction B is [tex]H_{2}O_{2}[/tex]. As 2 is coefficient of [tex]H_{2}O_{2}[/tex] so, 2 molecules are present on the reactant side of the equation.
The the products in Reaction B are [tex]H_{2}O[/tex] and [tex]O_{2}[/tex]. The coefficient of [tex]H_{2}O[/tex] is 2 and coefficient of [tex]O_{2}[/tex] is 1. Hence, there are total (2 + 1) equals to 3 molecules present on the product side of the equation.
Thus, we can conclude that:
The reactant in Reaction B is [tex]H_{2}O_{2}[/tex].
The products in Reaction B are [tex]H_{2}O[/tex] and [tex]O_{2}[/tex].
There are 2 molecules present on the reactant side of the equation.
There are 3 molecules present on the product side of the equation.
