Answer:
[tex]c=3.71\ J/g^{\circ} C[/tex]
Explanation:
Given that,
Mass of sample, m = 996.9 g
The change in temperature of the sample, [tex]\Delta T=-70.98^{\circ}C[/tex]
Heat produced, Q = 62.9 calories = 263173.6 J
The heat released by a sample due to change in temperature is given by :
[tex]Q=mc\Delta T[/tex]
Where
c is the specific heat capacity
So,
[tex]c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{263173.6}{996.9\times 70.98}\\\\c=3.71\ J/g^{\circ} C[/tex]
So, the specific heat of ethanol is equal to [tex]3.71\ J/g^{\circ} C[/tex].
