Fay read an article that said 26% of Americans can speak more than one language. She was curious if this
figure was higher in her city, so she tested H, : p=0.26 vs. H : p > 0.26, where p represents the
proportion of people in her city that can speak more than one language.
She found that 40 of 120 people sampled could speak more than one language. The test statistic for these
results was 2 1.83.
Assuming that the necessary conditions are met, what is the approximate P-value for Fay's test?
You may round to three decimal places.
P-value

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Respuesta :

marianna33 marianna33 · Answer 1 · 2021-05-14T02:07:19+02:00

Answer:

0.0336

Step-by-step explanation:

the hint says so

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joaobezerra joaobezerra · Answer 2 · 2022-02-15T11:41:32+01:00

According to the result of the test statistic, the approximate p-value for Fay's test is of 0.034.

It depends on the test statistic z, as follows.

For a left-tailed test, it is the area under the normal curve to the left of z, which is the p-value of z.

For a right-tailed test, it is the area under the normal curve to the right of z, which is 1 subtracted by the p-value of z.

For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is 2 multiplied by 1 subtracted by the p-value of z.

In this problem, we are testing if the proportion is greater than a value, hence it is a right-tailed test.

The test statistic is z = 1.83, which has a p-value of 0.966.

1 - 0.966 = 0.034.

Hence, the approximate p-value for Fay's test is of 0.034.

You can learn more about p-values at brainly.com/question/13873630