Answer:
[tex]\boxed {\boxed {\sf 39, 225 \ Joules}}}[/tex]
Explanation:
Since we are given the mass, temperature, and specific heat, we should use the following formula to calculate heat energy.
[tex]q=mc \Delta T[/tex]
We have 375 grams of water, the specific heat of water is 4.184 J/g ° C, and the temperature is raised 25 degrees Celsisus. Therefore:
- m= 375 g
- c= 4.184 J/g °C
- ΔT= 25°C
Substitute the values into the formula.
[tex]q= (375 \ g)(4.184 \ J/g \textdegree C)(25 \textdegree C)[/tex]
Multiply the first two values together. The units of grams will cancel.
[tex]q=1569 \ J/ \textdegree C(25 \textdegree C)[/tex]
Multiply again. This time, the degrees Celsius cancel, so we are left with only the units of Joules.
[tex]q= 39225 \ J[/tex]
39,255 Joules of heat must be absorbed by the water.
