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msm555

Answer:

Solution given:

diameter [d]=16m

radius [r]=8m

let slant height =l

surface area =628.32m²

πr(r+l)=628.32m²

π×8(8+l)=628.32

8+l=628.32/(8π)

8+l=25

l=25-8

l=17m

now

height of cone [h]=√{17²-8²}=15m

Again

Volume of cone =⅓πr²h=⅓×π×8²×15=320π 0r 1005.31m³

The required volume is 320π 0r 1005.31m³

The Volume of the given Cone is: 1005.469 cubic. cm.

V=1005.469 cubic. cm.

What is Volume of cone?

The volume of a 3 -dimensional solid is the amount of space it occupies.

The volume V of a cone with radius r is one-third the area of the base B times the height h .

V= [tex]\frac{1}{3} \pi r^{2} h[/tex]

Surface area of cone= 628.32

[tex]\pi r(l+r)[/tex]= 628.32

3.14 x 8 (l + 8)= 628.32

l+8= 25.01

l= 17.01 cm

height= 15.01 cm

Now volume of cone,

V= [tex]\frac{1}{3} \pi r^{2} h[/tex]

  = [tex]\frac{1}{3} *3.14 *8^{2}* 15.01[/tex]

  =1005.469 cubic. cm.

volume of cone, V= 1005.469 cubic. cm.

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