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Answer:

[0] real zeros

Step-by-step explanation:

You can use the discriminant of the quadratic formula which is b² – 4ac to determine the # of real zeros by knowing that:

  • 2 real zero(s) occur when b² – 4ac > 0.
  • 1 real zero(s) occur when b² – 4ac = 0.
  • 0 real zero(s) occur when b² – 4ac < 0.

Taking into account the definition of zeros of a function, the function has no real roots and its graph does not intersect the x-axis.

Zeros of a function

The function f(x) = ax²  + bx + c

with a, b, c real numbers and a ≠ 0, is a function  quadratic expressed in its polynomial form (It is so called because the function is expressed by a polynomial).

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

That is, the zeros represent the roots of the polynomial equation that is obtained by making f(x)=0.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

The following expression is called discriminant:

Δ= b²- 4×a×c

The discriminant determines the amount of  roots of the function. Then:

  • If Δ <0 the function has no real roots and its graph does not intersect the x-axis.
  • If Δ> 0 the function has two real roots and its graph intersects the x-axis at two points .
  • If Δ = 0 the function has a real root and its graph intersects the x-axis at a single point that coincides with its vertex. In this case the function is said to have a double root.

Amount of roots in this case

In this case, the function is f(x) = 3x²  + 5x + 17, where:

  • a= 3
  • b= 5
  • c= 17

Replacing in the definition of discriminant:

Δ= 5²- 4×3×17

and solving you get:

Δ= 25- 204

Δ= -179

Since Δ< 0, the function has no real roots and its graph does not intersect the x-axis.

Learn more about the zeros of a quadratic function:

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