Answer:
V = 29 + j3
Step-by-step explanation:
4+j3 amps and resistance of 5-j3 ohms what is the voltage of the circuit
V = IR I = 4+j3 amps R = 5-j3 ohms
V = 4+j3 × 5-j3
V = [4 × 5]+[j3 × -j3] + [4 × -j3] + [j3 × 5]
V = 20 + (-j²)9 + (-j12) + j15
V = 20 - 9 + j3 j3 × -j3 = 9 not -9 j = -1 j × j = -1 not 1 my mistake
V = 11 + j3 WRONG
my daughter's old TI 84 Plus Silver Edtion calculator got 29+j3
