graph ksjfkdkdkdkdkfkfk

Answer:
See attachment >_<
Step-by-step explanation:
Because the line includes the point [tex](0,3)[/tex], we'll begin our line at this coordinate.
The slope is [tex]7[/tex], or, [tex]\frac{7}{1}[/tex]. Slope is formatted in the [tex]rise[/tex] in the line over its [tex]run[/tex]. Or, [tex]\frac{rise}{run}[/tex]. This means the line rises [tex]7[/tex] units and runs [tex]1[/tex] unit.
From our beginning point, [tex](0,3)[/tex], move up seven units and then to the right one unit.
If this line was negative (it would have a negative slope), we would run to the left. However, we have a positive slope, so we will run to the right.
By doing this, we land on the point [tex](1,10)[/tex]. Draw a line through this point with our beginning coordinate [tex](0,3)[/tex]. This is our graphed line. I've attached a photo as well :)
Good luck ^^
Answer:
the answer is the 3rd one down fnivjgoibjmvkmkfmvk
Step-by-step explanation: