Answer: 2144
Step-by-step explanation:
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The summation of this series is 5940 for n takes 0,1,2,3,4.
These functions use addition to sum up a series of numbers by solving the integer variable x from numeric constant, whose value is the sum of the each number in the sequence is summation.
For the given situation,
The series is ∑n = 132(4n+1)
Let us consider ∑n=4
So n takes the value, n=0,1,2,3,4.
⇒[tex]132(4(0)+1)+132(4(1)+1)+132(4(2)+1)+132(4(3)+1)+132(4(4)+1)[/tex]
⇒ [tex]132+660+1188+1716+2244[/tex]
⇒ [tex]5940[/tex]
Hence we can conclude that the summation of this series is 5940 for n takes 0,1,2,3,4.
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