Using the combination formula, it is found that 4845 combinations of four students are possible.
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this problem, four students are taken from a set of 20, hence the number of combinations is given by:
[tex]C_{20,4} = \frac{20!}{4!16!} = 4845[/tex]
More can be learned about the combination formula at https://brainly.com/question/25821700
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