The value of x for the given quadratic equation is (19+[tex]\sqrt{1261}[/tex])/50,
(19-[tex]\sqrt{1261}[/tex])/50.
What is a quadratic equation?
It is in the form of a[tex]x^{2} +bx+c[/tex]. It is simply an equation and we have to solve for x.
How to solve a quadratic equation?
If we solve the given equation we will be able to get the following equation
[tex]25x^{2} -19x-9=0[/tex]
x=(-b+-[tex]\sqrt{b^{2}-4ac }[/tex])/2a
when we put b=19 a =25 c =-9
we will get x=[tex](19+\sqrt{1261} )/50 , (19-\sqrt{1261} )/50[/tex].
Learn more about quadratic equations at https://brainly.com/question/1214333
#SPJ2
