Respuesta :
Answer: The specific heat capacity of the sample is [tex]0.899 J/g^{o}C[/tex] and as heat is released in this reaction so it is exothermic in nature.
Explanation:
Given: Mass = 120.4 g
Heat energy released = -7020 J
Initial temperature = [tex]90.5^{o}C[/tex]
Final temperature = [tex]25.7^{o}C[/tex]
Formula used is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass of substance
C = specific heat capacity
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\-7020 J = 120.4 g \times C \times (90.5 - 25.7)^{o}C\\C = \frac{-7020 J}{120.4 \times (-64.8^{o}C)}\\= \frac{7020 J}{7801.92} J/g^{o}C\\= 0.899 J/g^{o}C[/tex]
When heat is released in a process or reaction then it means it is exothermic in nature.
Thus, we can conclude that the specific heat capacity of the sample is [tex]0.899 J/g^{o}C[/tex] and as heat is released in this reaction so it is exothermic in nature.
