Answer: The total pressure of given mixture that contains 3 gases is 7.68 atm.
Explanation:
Given: Partial pressure of gases is:
Gas A = 4.2 atm
Gas B = 780 mm Hg
Convert mm Hg into atm is as follows.
[tex]1 mm Hg = 0.00131579 atm\\780 mm Hg = 780 mm Hg \times \frac{0.00131579 atm}{1 mm Hg}\\= 1.02 atm[/tex]
Gas C = 250 kPa
Convert kPa into atm as follows.
[tex]1 kPa = 0.00986923 atm\\250 kPa = 250 kPa \times \frac{0.00986923 atm}{1 kPa}\\= 2.46 atm[/tex]
Total pressure is the sum of partial pressures of gases present in the mixture.
Therefore, total pressure of given mixture is calculated as follows.
[tex]P_{total} = P_{A} + P_{B} + P_{C}\\= 4.2 atm + 1.02 atm + 2.46 atm\\= 7.68 atm[/tex]
Thus, we can conclude that the total pressure of given mixture that contains 3 gases is 7.68 atm.
