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On a hot day, a 15.0 kg window increased from 20.0 degrees C to 26.7 degrees C. How much heat energy did the glass window absorb? (specific heat of glass = 0.840 J/gC)

Respuesta :

Answer: The heat energy absorbed by the glass window is 84420 J.

Explanation:

Given: Mass = 15.0 kg (1 kg = 1000 g) = 15000 g

Specific heat capacity = [tex]0.840^{o}C[/tex]

Initial temperature = [tex]20^{o}C[/tex]

Final temperature = [tex]26.7^{o}C[/tex]

Formula used to calculate heat energy is as follows.

[tex]q = m \times C \times (T_{2} - T_{1})[/tex]

where,

q = heat energy

m =  mass of substance

C = specific heat capacity

[tex]T_{1}[/tex] = initial temperature

[tex]T_{2}[/tex] = final temperature

Substitute the values into above formula as follows.

[tex]q = m \times C \times (T_{2} - T_{1})\\= 15000 g \times 0.840J/g^{o}C \times (26.7 - 20.0)^{o}C\\= 84420 J[/tex]

Thus, we can conclude that heat energy absorbed by the glass window is 84420J.