An 18.0 g sample of unidentified metal was heated from 21.5°C to 89.0°C.
292 J of heat energy was absorbed by the metal in the heating process.
Calculate the specific heat of the metal to determine its identity.(need work show, or how you got the answer)

A.calcium
B.iron
C.copper
D.silver

An 180 g sample of unidentified metal was heated from 215C to 890C 292 J of heat energy was absorbed by the metal in the heating process Calculate the specific class=

Respuesta :

Answer: (d)-Silver

Explanation:

Given

The mass of sample is [tex]m=18\ gm[/tex]

It is heated from [tex]21.5^{\circ}C[/tex] to [tex]89^{\circ}C[/tex]

heat energy absorbed is [tex]292\ J[/tex]

Heat absorbed is given by [tex]Q=mc\Delta T[/tex]

Insert the values

[tex]\Rightarrow 292=18\times c\times [89-21.5]\\\Rightarrow 292=18\times c\times 67.5\\\\\Rightarrow c=\dfrac{292}{1215}\\\\\Rightarrow c=0.24\ J/g^{\circ}C[/tex]

As per the table, it is Silver