lionrog56 lionrog56
  • 12-05-2021
  • Mathematics
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If /\PQR~/\SQT, find the value of x.

If PQRSQT find the value of x class=

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Hamed313
Hamed313 Hamed313
  • 12-05-2021

Answer:

[tex] \frac{x + 13}{8} = \frac{21}{x - 9} \\ {x}^{2} + 4x - 117 = 168 \\ {x}^{2} + 4x - 285 = 0 \\ (x - 15)(x + 19) = 0 \\ x = 15 \\ x = - 19[/tex]

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