Answer:
Step-by-step explanation:
Tan(theta) = Sin(theta) / cos(theta)
1/4 = sin(theta) / sqrt(1 - sin^2(theta) ) Cross multiply
sqrt(1 - sin^2(theta)) = 4*sin^2(theta) Square both sides.
1 - sin^2(theta) = 16 * sin^4 (theta) Transfer the left side to the right side.
0 = 16 sin^4(theta) + sin^2(theta) - 1
Use the quadratic formula to find a value for sin^2(theta)
a = 16
b = 1
c = - 1
I'll leave solving the quadratic to you.
There are two answers
sin^2(theta)= .22069
The other root is - 0.28 which you cannot use.
Sin(theta) = +/- 0.4698
Cos(theta) is < 0 in quads 2 and 3
So sin(theta) is positive in quad 2
and sin(theta) is minus in quad 3
