Whats the Diameter? I really need help understanding this
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Answer:
1.8 in.
Step-by-step explanation:
Hi there!
1) Determine the radius of the base
[tex]V=\frac{1}{3} \pi r^2h[/tex] where r is the radius of the base and h is the height of the cone
Plug in the known values (h=4.2, V=3.6)
[tex]3.6=\frac{1}{3} \pi r^2(4.2)[/tex]
Isolate r; divide both sides by 4.2
[tex]\frac{3.6}{4.2} =\frac{1}{3} \pi r^2\\\frac{6}{7} =\frac{1}{3} \pi r^2[/tex]
Multiply both sides by 3
[tex]\frac{6}{7}*3 =\pi r^2\\\frac{18}{7}=\pi r^2[/tex]
Divide both sides by π
[tex]\frac{18}{7\pi }=r^2[/tex]
Take the square root of both sides
[tex]\sqrt{\frac{18}{7\pi }} =r[/tex]
2) Determine the diameter
Now that we have the radius, to find the diameter, multiply r by 2:
[tex]d=\sqrt{\frac{18}{7\pi }}*2\\d=1.8[/tex]
Therefore, the diameter is 1.8 in. when rounded to the nearest tenth.
I hope this helps!
Answer:
1.8 in
Step-by-step explanation:
we know the equation for the volume of a cone is pi*r^2 h/3=3.6
pi r^2 *4.2=10.8
solve for r
r is about 0.9 so diameter is 1.8 in