Answer:
The ration of molar concentration is "2.5".
Explanation:
The given values are:
Average density of salt water,
= [tex]1.03 \ g/cm^3[/tex]
Net pressure,
= [tex]2.00 \ atm[/tex]
Increase in pressure,
= [tex]1.00 \ atm[/tex]
Now,
The under water pressure will be:
= [tex]\frac{15 \ m}{10}\times 1 \ atm +1 \ atm[/tex]
= [tex]1.5\times 1+1[/tex]
= [tex]1.5+1[/tex]
= [tex]2.5 \ atm[/tex]
hence,
The ratio will be:
= [tex]\frac{(\frac{n}{V})_{15m} }{(\frac{n}{V})_{surface} }[/tex]
or,
= [tex]\frac{P}{P_s}[/tex]
= [tex]\frac{2.5}{1}[/tex]
= [tex]2.5[/tex]