Answer:
CI = (0.68, 3.84)
Step-by-step explanation:
We want to find the confidence interval for the difference in means between the two groups MC and MN.
where;
- MC represents the mean increase in flow-mediated dilation for people eating dark chocolate every day.
- MN represents the mean increase in flow-mediated dilation for people eating a dark chocolate substitute each day.
We are given;
Sample mean of C; x'c = 1.3
Sample mean of N; x'n = -0.96
Standard deviation of C; S_c = 2.32
Standard deviation of N; S_n = 1.58
Sample size of C; n_c = 11
Sample size of N; n_n = 10
Formula for the confidence interval for the difference in means is;
CI = (x'c - x'n) ± t√[(S_c²/n_c) + (S_n²/n_n)]
Where t is critical value at confidence level. From table attached, t at CL of 90% with DF = 10 - 1 = 9 is; t = 1.833
Thus;
CI = (1.3 - (-0.96)) ± 1.833√[(2.32²/11) + (1.58²/10)]
CI = [(1.3 + 0.96)) - 1.833√[(2.32²/11) + (1.58²/10)], [(1.3 + 0.96)) + 1.833√[(2.32²/11) + (1.58²/10)]
CI = (2.26 - 1.58), (2.26 + 1.58)
CI = (0.68, 3.84)