Answer:
[tex]238.5gCuSO_4[/tex]
Explanation:
Hello there!
In this case, by considering the given chemical reaction, it is possible for us to calculate the required grams of CuSO4 by considering its molar mass of 159.6 g/mol, the given molecules of NaBr, the Avogadro's number and the 1:2 mole ratio between these two in order to set up the following stoichiometric set up:
[tex]1.80x10^{24}moleculesNaBr*\frac{1molNaBr}{6.022x10^{23}molecules NaBr}*\frac{1molCuSO_4}{2molNaBr} *\frac{159.6gCuSO_4}{1molCuSO_4}\\\\=238.5gCuSO_4[/tex]
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