Answer:
[tex]P \approx 225atm[/tex]
Explanation:
From the question we are told that:
Moles of sample n=3.20_mol
Volume V=350mL
Temperature T=300k
Generally the equation for ideal gas is mathematically given by
[tex]PV=nRT[/tex]
[tex]P=\frac{nRT}{V}[/tex]
[tex]P=\frac{3.20*0.08206*300}{350*10^{-3}}[/tex]
[tex]P=225.079atm[/tex]
[tex]P \approx 225atm[/tex]
