Unit l2 trigonometry homework 6 law of cosines
Does anyone know the answer please help!
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Step-by-step explanation:
The law of cosine states that:
[tex]C^2=B^2+A^2-2AB\cos(\theta)[/tex], where C is the side opposite of angle theta, and A and B are the adjacent sides of the angle.
In this case, A is equal to 21, and B is equal to 30 (or it could also be the other way around). That means that:
[tex]C^2=21^2+30^2-2\cdot21\cdot30\cos(73)\\C=\sqrt{21^2+30^2-2\cdot21\cdot30\cos(73)}=\boxed{31.186722}[/tex] (to nearest 6 digits)
Answer:
102.61
Step-by-step explanation:
assuming that QS is the hypothesis we us the fromula like this:
[tex]30cos(73)[/tex]
which gives us 8.7711511417 or we can round to 8.77
assuming that QS is the adjacent we use:
[tex]\frac{30}{cos(73)}[/tex]
which gives us 102.609108595 or rounded to 102.61
looking at both answers we can see that 102.61 would be the correct answer.