Solve the following system of equations algebraically:
y = x^2 – 10x + 15
y = 2x – 5

Answer:
(2, -1)
(10, 15)
Step-by-step explanation:
Subtract the second equation from the first
y = x² – 10x + 15
- (y = 2x – 5)
————————————
0 = x² - 12x + 20
Factor
(x - 2)(x - 10) = 0
x = {2, 10}
-------------------
For x = 2
y = 2(2) - 5
y = -1
Solution 1
(2, -1)
----------------------
For x = 10
y = 2(10) - 5
y = 15
Solution 2
(10, 15)