Respuesta :
Answer:
[tex](1)\ [12]x^2 [-][37]x - 30 = (3x + 2)(4x - 15)[/tex]
[tex](2)\ x^2\ [\ -]\ 169 = (x \[+ ]\ 13){x\ [- ]\ [13 ])[/tex]
[tex](3)\ x^2 [-]\ [9]x + 20 = (x\ [-] 5)(x- [4])[/tex]
[tex](4)\ x^2 + [11]x + 28 = (x + 7)(x + [4])[/tex]
[tex](5)\ x^2 + [5]x - 24 = (x\ [-]\ [3])(x\ [+]\ [8])[/tex]
Step-by-step explanation:
Given
See attachment for complete question
Required
Complete the boxes
Solving (1):
[tex][ \ ]x^2 [ \ ] [\ ]x - 30 = (3x + 2)(4x - 15)[/tex]
Swap the equation
[tex](3x + 2)(4x - 15) = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]
Open bracket
[tex]12x^2 -45x + 8x - 30 = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]
Simplify the like terms
[tex]12x^2 -37x - 30 = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]
So, we have:
[tex][12]x^2 [-][37]x - 30 = [ \ ]x^2 [ \ ] [\ ]x - 30[/tex]
i.e.
[tex][12]x^2 [-][37]x - 30 = (3x + 2)(4x - 15)[/tex]
Solving (2):
[tex]x^2\ [\ ]\ 169 = (x \ [\ ]\ 13)(x\ [\ ]\ [\ ])[/tex]
The above expression illustrates the difference of two squares.
So, complete the first equation with minus
[tex]x^2\ [\ -]\ 169 = (x \ [\ ]\ 13)(x\ [\ ]\ [\ ])[/tex]
Express 169 as 13^2
[tex]x^2\ [\ -]\ 13^2 = (x \ [\ ]\ 13)(x\ [\ ]\ [\ ])[/tex]
Apply difference of two squares
[tex](x + 13)(x - 13) = (x \[\ ]\ 13){x\ [\ ]\ [\ ])[/tex]
So, the complete expression is:
[tex]x^2\ [\ -]\ 169 = (x \[+ ]\ 13){x\ [- ]\ [13 ])[/tex]
Solving (3):
[tex]x^2 [\ ]\ [\ ]x + 20 = (x \ [\ ]5)(x - [\ ])[/tex]
20 can be expressed as: -5 * -4
So, the expression becomes
[tex]x^2 [\ ]\ [\ ]x + 20 = (x \ [- ]5)(x - [4 ])[/tex]
Expand
[tex]x^2 [\ ]\ [\ ]x + 20 = x^2 - 5x - 4x + 20[/tex]
[tex]x^2 [\ ]\ [\ ]x + 20 = x^2 -9x + 20[/tex]
So, the complete expression is:
[tex]x^2 [-]\ [9]x + 20 = (x\ [-] 5)(x- [4])[/tex]
Solving (4):
[tex]x^2 + []x + 28 = (x + 7)(x + [])[/tex]
28 can be expressed as 7 * 4
So, the expression becomes
[tex]x^2 + []x + 28 = (x + 7)(x + [4])[/tex]
Expand
[tex]x^2 + []x + 28 = x^2 + 7x + 4x + 28[/tex]
[tex]x^2 + []x + 28 = x^2 + 11x + 28[/tex]
So, the complete expression is:
[tex]x^2 + [11]x + 28 = (x + 7)(x + [4])[/tex]
Solving (5):
[tex]x^2 + []x - 24 = (x\ []\ [])(x\ []\ [])[/tex]
-24 can be expressed as -3 * 8
So, the expression becomes
[tex]x^2 + []x - 24 = (x\ [-]\ [3])(x\ [+]\ [8])[/tex]
Expand
[tex]x^2 + []x - 24 = x^2 +8x - 3x - 24[/tex]
[tex]x^2 + []x - 24 = x^2 +5x - 24[/tex]
So, the complete expression is:
[tex]x^2 + [5]x - 24 = (x\ [-]\ [3])(x\ [+]\ [8])[/tex]
An equation is formed of two equal expressions. The complete equations are:
- [tex]12x^2-37x-30 = (3x+2)(4x-15)[/tex]
- [tex](x^2-169) = (x+13)(x-13)[/tex]
- [tex]x^2-9x+20=(x-5)(x-4)[/tex]
- [tex]x^2 + 11x + 28 = (x+7)(x+4)[/tex]
- [tex]x^2 + 5x - 24=(x+8)(x-3)[/tex]
What is an equation?
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
1. The first equation that is given to us is:
[tex](?x^2)\ ?\ (?x)-30 = (3x+2)(4x-15)[/tex]
Now, if we simply expand the right-hand side of the equation we will get the equation that is mentioned on the left side of the given equation, therefore,
[tex](3x+2)(4x-15)\\\\= 12x^2-45x+8x-30\\\\=12x^2-37x-30[/tex]
Thus, the complete equation will be
[tex]12x^2-37x-30 = (3x+2)(4x-15)[/tex].
2. The second equation that is given to us is,
[tex]x^2\ ?\ 169 = (x\ ?\ 13)(x\ ?\ ?)[/tex]
Now, if look closely at the equation, and substitute the '-' in the place of '?' the equation we will be in the form of an algebraic equation, therefore, the solution of the equation can be made using the algebraic expression,
[tex]a^2-b^2 = (a+b)(a-b)\\\\(x^2-13^2) = (x+13)(x-13)\\\\\(x^2-169) = (x+13)(x-13)[/tex]
Thus, the complete equation will be
[tex](x^2-169) = (x+13)(x-13)[/tex].
3. The third equation that is given to us is,
[tex]x^2\ ?\ (?x)+20 = (x\ ?\ 5)(x-?)[/tex]
As we can see in the equation, on the left side of the equation the last digit is +20, therefore, the digits on the right side of the equation should be such that their product should be +20, as 5 is already given therefore, the other term should be 4 also, the second term is positive but we need the product to be positive, therefore, the sign of the digit 5 will also be negative.
[tex]x^2\ ?\ (?x)+20 = (x\ ?\ 5)(x-?)\\\\x^2\ ?\ (?x)+20 = (x- 5)(x-4)[/tex]
Now, if we solve the right side of the equation we will get the left side of the equation,
[tex](x- 5)(x-4)\\\\= x^2 - 4x-5x +20\\\\=x^2-9x+20[/tex]
Thus, the complete equation is
[tex]x^2-9x+20=(x-5)(x-4)[/tex].
4. The fourth equation that is given to us is
[tex]x^2 + ?x + 28 = (x+7)(x+?)[/tex]
As we can see in the equation, on the left side of the equation the last digit is +28, therefore, the digits on the right side of the equation should be such that their product should be +28, as 7 is already given therefore, the other term should be 4. Also, 28 is a positive integer, and 7 is also a positive integer, therefore, the number in the last will be positive as well.
[tex]x^2 + ?x + 28 = (x+7)(x+4)[/tex]
Now, if we solve the right side of the equation we will get the left side of the equation,
[tex](x+7)(x+4)\\\\= x^2 + 4x+ 7x + 28\\\\= x^2 + 11x+28[/tex]
Thus, the complete equation is
[tex]x^2 + 11x + 28 = (x+7)(x+4)[/tex]
5. The fifth equation that is given to us is
[tex]x^2 + ?x -24=(x\ ?\ ?)(x\ ?\ ?)[/tex]
As we can see in the equation, on the left side of the equation the last digit is -24, therefore, the digits on the right side of the equation should be such that their product should be -24, Since the product is negative, therefore, either one of the digits on the right should be negative as well, but the middle term on the right is positive, therefore, the bigger number will be positive while the smaller ones will be negative.
[tex]x^2 + ?x -24=(x+8)(x-3)[/tex]
Now, solving the right side of the equation to get the complete left side of the equation we will get,
[tex](x+8)(x-3)\\\\=x^2 -3x + 8x -24\\\\=x^2 + 5x - 24[/tex]
Thus, the complete equation is
[tex]x^2 + 5x - 24=(x+8)(x-3)[/tex]
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