Jerome, kevin and seth shared a submarine sandwhich. Jerome ate 1/2 of the sandwich , kevin ate 1/3 of the sandwich, and seth ate the rest. What is the ratio of jerome's share to kevin's share to kevin's share to seth's share?

Respuesta :

Given:

Jerome ate 1/2 of the sandwich , Kevin ate 1/3 of the sandwich, and Seth ate the rest.

To find:

The ratio of jerome's share to kevin's share to seth's share.

Solution:

Jerome ate 1/2 of the sandwich. So,

Jerome's share = [tex]\dfrac{1}{2}[/tex]

Kevin ate 1/3 of the sandwich. So,

Kevin's share = [tex]\dfrac{1}{3}[/tex]

Seth ate the rest. So,

Seth's share = [tex]1-\dfrac{1}{2}-\dfrac{1}{3}[/tex]

                     = [tex]\dfrac{6-3-2}{6}[/tex]

                    = [tex]\dfrac{1}{6}[/tex]

The ratio of jerome's share to kevin's share to seth's share is:

[tex]\dfrac{1}{2}:\dfrac{1}{3}:\dfrac{1}{6}[/tex]

To simplify the ratio multiply the ratio by 6.

[tex]\dfrac{1}{2}\times 6:\dfrac{1}{3}\times 6:\dfrac{1}{6}\times 6[/tex]

[tex]3:2:1[/tex]

Therefore, the ratio of jerome's share to kevin's share to seth's share is 3:2:1.