Answer: The volume at 600 K will be 0.050 L.
Explanation:
Given: [tex]V_{1}[/tex] = 0.025 L, [tex]T_{1}[/tex] = 300 K
[tex]V_{2}[/tex] = ?, [tex]T_{2}[/tex] = 600 K
Formula used is as follows.
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.025 L}{300 K} = \frac{V_{2}}{600 K}\\V_{2} = 0.050 L[/tex]
Thus, we can conclude that the volume at 600 K will be 0.050 L.
