Respuesta :
PLEASE MARK BRAINLIEST IF CORRECT
I believe that you would need to distribute the numbers outside of the parentheses (2,5,4,6) into the parentheses.
2(x+3)=
2x+6
5(2x-4)=
10x-20
4(2x-4)=
8x-16
6(x-4y)=
6x-24y
I believe that you would need to distribute the numbers outside of the parentheses (2,5,4,6) into the parentheses.
2(x+3)=
2x+6
5(2x-4)=
10x-20
4(2x-4)=
8x-16
6(x-4y)=
6x-24y