Answer:
Step-by-step explanation:
Use the property,
"Measure of an arc is equal to the measure of the central angle subtended by the arc at the center of a circle"
a). m∠JQN = 90°
Therefore, m(arc JN) = 90°
b). m(arc KL) = m(arc JM) - [m(arc JK) + m(arc LM)]
= 180° - (56° + 98°)
= 180° - 154°
= 26°
c). m(arc NK) = m(arc JN) + m(arc JK)
= 90° + 56°
= 146°
d). m(arc NML) = m(arc NM) + m(arc ML)
= 90° + 98°
= 188°
e). m(arc MNL) = m(arc MJ) + m(arc JK) + m(arc KL)
= 180° + 56° + 26°
= 262°
