Answer: The new pressure is 1.34 atm.
Explanation:
Given: [tex]P_{1}[/tex] = 10.8 atm, [tex]T_{1} = 118^{o}C[/tex]
[tex]P_{2}[/tex] = ?, [tex]T_{2} = 948^{o}C[/tex]
Formula used to calculate the new pressure is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{10.8 atm}{118^{o}C} = \frac{P_{2}}{948^{o}C}\\P_{2} = 1.34 atm[/tex]
Thu, we can conclude that the new pressure is 1.34 atm.
