Respuesta :
If this helps you have to use the formula (x1,y1) and (x2,y2). So for number 1 it would be 7x - 3x and 2y - 4y
[tex]1.7x \times 2x - 4y \times 3x \\ 7x \times 3x - 4y \times 2y \\ 21x ^{2} - {8}y^{2} \\ 2.3x \times 2x - 4y \times 3y \\ 6x ^{2} - {12y}^{2} \\ 3.4x \times 5x - 5x \times 4x \\ {20x}^{2} - {20x }^{2} \\ 0 [/tex]