Answer:
[tex]q=1118.865W[/tex]
Explanation:
From the question we are told that
Diameter of the cylinder [tex]D=0.3m[/tex]
Length of the cylinder [tex]L=1.75m[/tex]
Surface temperature of cylinder [tex]T_s=30 \textdegree C=303k[/tex]
Speed of air [tex]V=10m/s[/tex]
Temperature of air [tex]T=20 \textdegree C[/tex]
Generally the equation for Reynolds number is mathematically given by
[tex]Re_D=\frac{VD}{v}[/tex]
where
[tex]v=15.27*10^-^6[/tex]
[tex]Re_D=\frac{10*0.3}{15.27*10^-^6}[/tex]
[tex]Re_D=1.96*10^5[/tex]
Generally the equation for Nusselt number is mathematically given by
[tex]N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}[/tex]
where
Prandtl number
[tex]Pr=0.71[/tex]
[tex]N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}[/tex]
[tex]N_u=0.6(1.96*10^5)^{0.6}(0.71)^{0.37}[/tex]
[tex]N_u=791.53[/tex]
Generally the equation for convective heat transfer is mathematically given by
[tex]h=Nu \frac{k}{D}[/tex]
where
[tex]k=25.7*10^{-3}[/tex]
[tex]h=791.53*\frac{25.7*10^{-3}}{0.3}[/tex]
[tex]h=67.81W/m^2K[/tex]
Generally the equation for surface area of a cylinder is mathematically given by
[tex]A=\pi DL[/tex]
[tex]A=\pi *0.3*1.75[/tex]
[tex]A=1.65m^2[/tex]
Generally the equation for convective heat transfer is mathematically given by
[tex]q=h4(T_s-T_{inty)}[/tex]
[tex]q=(67.81)*1.65*(30-20)\\[/tex]
[tex]q=1118.865W[/tex]
