Answer:
a)
[tex]v = 4.048 *10^6[/tex] m/s
b)
Angular frequency = [tex]1.92 * 10^7[/tex]
Explanation:
As we know
[tex]v = \frac{qBr}{m}[/tex]
q is the charge on the electron = [tex]3.2 * 10^{-19}[/tex] C
B is the magnetic field in Tesla = [tex]0.4[/tex] T
r is the radius of the circle = [tex]0.21[/tex] m
mass of the electrons = [tex]6.64 * 10^{-27}[/tex] Kg
a)
Substituting the given values in above equation, we get -
[tex]v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6[/tex]m/s
b)
Angular frequency =
[tex]\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7[/tex]
