Find the area of this triangle.
Round to the nearest tenth.
12 cm
33°
5.5 cm
[?] cm2

Answer:
1/2 ab sinC =1/2(5.5×12)sin33 = 17.97
Step-by-step explanation:
Put the numbers in the equation ,a calculator will be better.
The area of the triangle is 18.0cm².
The sine rule for the area of the triangle is defined as the area of the triangle that can be calculated by the product of the half of the two sides of the triangle and the sine of the angle between the two sides.
Area= Δ= (1/2)*a*b*sinC
where a and b are the length of the side BC and AC respectively. And angle C is the angle between the sides BC and AC.
Here given in the figure the triangle has two sides of lengths 12cm, and 5.5cm.
The angle between the sides is 33°.
Then using the sine rule for the area of the triangle
The area of the triangle= (1/2)*a*b*sinC
=(1/2)*12*5.5*sin 33°
=17.97≅ 18.0 cm²
Therefore the area of the triangle is 18.0cm².
Learn more about the sine rule
here: https://brainly.com/question/27174058
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