A 5.0L balloon in a freezer is at a temperature of - 50 degrees * C has a pressure of 800 mm Hg. What will be the new pressure if the balloon is taken out and placed in a warm room (Temperature 37°C) and the volume expands to 7.0 L?

We are going to be using the Combined Gas Law for this problem as well. Just to refresh out memory - the Combined Gas Law expresses the relationship between pressure, volume, and temperature (in KELVIN) of a fixed amount of gas. The equation itself? Right here: [tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Now, looking at the problem, let's assign the values to its corresponding variable:

P1 = 800mmHg; V1 = 5.0L; T1 = -50°C + 273 = 223K

V2 = 7.0L; T2 = 37°C + 273 = 310K; P2 = ?

We are looking to find the new pressure, a.k.a. P2. So, let's plug and chug the values into the equation.

Set up: [tex]\frac{(800 mmHg)(5.0L)}{223K} = \frac{(7.0L)(P_{2})}{310K}[/tex]

==> [tex]\frac{(800 mmHg)(5.0L)}{223K} * 310K = (7.0L)(P_{2})}[/tex]

==> [tex]P_{2} = \frac{(800 mmHg)(5.0L)}{223K} * \frac{310K}{7.0} }[/tex]

==> [tex]P_{2} =[/tex] 794.36 = 794 mmHg