Answer:
[tex]0.29887\ \text{V}[/tex]
Explanation:
A = Area = [tex]0.42\times0.54\ \text{m}^2[/tex]
B = Magnetic field = 1.7 T
[tex]\theta[/tex] = Angle that magnetic field makes with the plane of the loop = [tex]71^{\circ}[/tex]
t = Time = 0.42 s
EMF is given by
[tex]\varepsilon=A\cos\theta\dfrac{dB}{dt}\\ =\dfrac{0.42\times 0.54\times\cos 71^{\circ}\times 1.7}{0.42}\\ =0.29887\ \text{V}[/tex]
The magnitude of the average emf induced in the loop is [tex]0.29887\ \text{V}[/tex].
