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HI dissociates to form 12 and Hz: 2HI(g) → H2(g) + 12(9) If the concentration of Hl changes at a
rate of -0.45 mol L's? what is the rate of appearance of 12(g)?

Respuesta :

mickymike92

Based on the rate of disappearance of HI, the rate of appearance of I₂ is 0.225 mol/L/s.

What is rate of reaction?

The rate of a reaction is the rate at which reactant molecules are converted to product or the rate at which product molecules are formed.

  • Rate of reaction = change in concentration of reactant or product/time

From the equation of the reaction, 2 moles of HI produces 1 mole of I₂.

The rate of disappearance of HI is -0.45 mol/L/s

The rate of appearance of I₂ will be 0.45/2 mol/L/s = 0.225 mol/L/s.

Therefore, the rate of appearance of I₂ is 0.225 mol/L/s.

Learn more about rate of reaction at: https://brainly.com/question/24795637

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