Answer:
Mass of sodium metal is 130.87 gram
Explanation:
The complete reaction is
2 NaN3 --> 2 Na + 3 N2
We know that PV = nRT
n = [tex]\frac{PV}{RT}[/tex]
On substituting the given values, we get
[tex]n = \frac{\frac{99707}{101325}*75 }{0.082 *(273.15 +15)} \\n = 3.02[/tex]moles of N2
Sodium azide's molar mass
3.02 *(2/3) = 2.013 moles
Mass = 2.03 * 65.01 = 130.87 gram
