The question is incomplete, the complete question is;
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with =n10 to an orbital with =n8. Round your answer to 3 significant digits.
Answer:
162 * 10^-7 m
Explanation:
The Rydberg formula is;
1/λ= R(1/n2^2 - 1/n1^2)
R = Rydberg constant = 1.097 * 10^7 m-1
n2 = final state of the electron = 8
n1 = initial state of the electron = 10
Substituting values;
1/λ= 1.097 * 10^7(1/8^2 - 1/10^2)
1/λ= 1.097 * 10^7(1/64 - 1/100)
1 / λ = 1.097 10⁷ (0.015625 - 0.01)
1 /λ = 0.006170625 10⁷
λ = (0.006170625 10⁷)^-1
λ = 162 * 10^-7 m
