Answer:
[tex]4118\ g[/tex]
Explanation:
[tex]We\ are\ given,\\No.\ of\ moles\ of\ Na_2SO_4\ provided=29\ moles\\Hence,\\Now,\\Lets\ calculate\ the\ Gram\ Molecular\ Mass\ of\ Na_2SO_4.\\We\ know\ that,\\Gram\ Atomic\ Mass\ of\ Sodium(Na) \approx 23\ g\\Gram\ Atomic\ Mass\ of\ Sulphur(S) \approx 32\ g\\Gram\ Atomic\ Mass\ of\ Oxygen(O) \approx 16\ g\\Hence,\\We\ observe\ that,\\One\ molecule\ of\ Na_2SO_4\ is\ made\ up\ of\ 2\ Sodium\ Atoms,\ 1\\ Sulphur\ Atom\ and\ 4\ Oxygen\ Atoms.[/tex]
[tex]Hence,\\Gram\ Molecular\ Mass\ of\ Na_2SO_4=2*(GAM\ of\ Na)+1*(GAM\ of\ S)\\+4*(GAM\ of\ O)\\=2*23+1*32+4*16\\=46+32+64\\=46+96\\=142\ g[/tex]
[tex]Hence,\\We\ also\ know\ that,\\Mass\ of\ A\ Sample=No.\ of\ moles*Gram\ Molecular\ Mass\\Hence,\\Mass\ of\ 29\ moles\ of\ Na_2SO_4=29*142=4118\ g[/tex]
Answer:
4118.2
Explanation:
Given: 29 moles of na²[tex]So^{4}[/tex]
To find: In grams.
Solution: Wrong
If 1 na²[tex]So^{4}[/tex] is 142 grams, then 29 grams will be found if a set of fraction has been set up;
Let [tex]"x"[/tex] be the variable
[tex]\frac{142}{1} = \frac{29}{x}[/tex]
Cross multiply
[tex]\frac{142}{29}[/tex] [tex]= 4.9[/tex]
Correct Solution
Multiply 29 by 142 = 4118
