jalynndeshay jalynndeshay

15-04-2021
Mathematics

contestada

I needddd helppppp !!!what’s the answer ?

I needddd helppppp whats the answer class=

Respuesta :

jimrgrant1 jimrgrant1

15-04-2021

Answer:

cosA = [tex]\frac{8}{17}[/tex]

Step-by-step explanation:

Using the identity

cosA = [tex]\frac{1}{secA}[/tex] = [tex]\frac{1}{\frac{17}{8} }[/tex] = [tex]\frac{8}{17}[/tex]

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MathsQueen0123 MathsQueen0123

15-04-2021

Answer:

8/17

Step-by-step explanation:

sec A = Hypotenuse/ Adjacent = 17/8

cos A = Adjacent / Hypotenuse = 8/17

Hope this helps

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