Given:
The quadratic equation is:
[tex]6x^2-x-2=0[/tex]
To find:
The nature of the solutions by using the discriminant.
Solution:
If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then its discriminant is:
[tex]D=b^2-4ac[/tex]
If D<0, then both roots are complex.
If D=0, then both roots are real and equal.
If D>0, then both roots are real and distinct.
We have,
[tex]6x^2-x-2=0[/tex]
Here, [tex]a=6,b=-1,c=-2[/tex]. So, the value of the discriminant is:
[tex]D=(-1)^2-4(6)(-2)[/tex]
[tex]D=1+48[/tex]
[tex]D=49[/tex]
Since [tex]D>0[/tex], then both roots are real and distinct.
Hence, the discriminant of the given quadratic equation is 49 and both roots are real and distinct.
