Answer:
a) v = 345.5 m / s, b) f = 183.8 Hz, c) λ = 1,336 m
Explanation:
a) the speed of sound depends on the density of the medium and this depends on the temperature, therefore
v = [tex]v_o \ \sqrt{1+ \frac{T}{273} }[/tex]
where v₀ is the speed of sound at 0ºC v₀ = 331 m / s
v = 331 [tex]\sqrt{1 + \frac{24.5}{273} }[/tex]
v = 345.5 m / s
c) In the exercise they indicate that the flute is a tube with the two ends open, so that at each end there is a belly, the resonance is
λ / 2 = L
λ = 2L
λ = 2 0.668
λ = 1,336 m
b) let's apply the relationship between speed, wavelength and frequency
v = λ f
f = v /λ
f = 345.5 / 1.336
f = 183.8 Hz
