2) A balloon was inflated to a volume of 5.0 liters at a temperature of
7.0°C. It landed in an oven and was heated to 147°C. What is its new
volume?

In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:

[tex]\frac{V_2}{T_2}= \frac{V_1}{T_1}[/tex]

Thus, by solving for the initial volume, V1, and making sure we use the temperatures in Kelvin, we can calculate the final volume as shown below:

[tex]V_1= \frac{V_2T_1}{T_2} \\\\V_1= \frac{5.0L*(147+273)K}{(7.0+273)K} \\\\V_1=7.5L[/tex]

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2) A balloon was inflated to a volume of 5.0 liters at a temperature of 7.0°C. It landed in an oven and was heated to 147°C. What is its new volume?

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2) A balloon was inflated to a volume of 5.0 liters at a temperature of
7.0°C. It landed in an oven and was heated to 147°C. What is its new
volume?