Answer:
[tex]d = 1.2973\pi r^3[/tex]
Step-by-step explanation:
Given
[tex]R_1 = r[/tex]
[tex]R_2 = 0.3[/tex]
Required
The difference in their volumes
The volume of a sphere is:
[tex]V = \frac{4}{3}\pi r^3[/tex]
So, the difference d is:
[tex]d = \frac{4}{3}\pi [R_1^3 - R_2^3][/tex]
[tex]d = \frac{4}{3}\pi [r^3 - (0.3r)^3][/tex]
[tex]d = \frac{4}{3}\pi [r^3 - 0.027r^3][/tex]
[tex]d = \frac{4}{3}\pi *0.973r^3[/tex]
[tex]d = \frac{3.892}{3}\pi r^3[/tex]
[tex]d = 1.2973\pi r^3[/tex]
Volume is a three-dimensional scalar quantity. The difference in the volume between a sphere with radius r and a sphere with radius 0.3r is 4.0757r³ unit³.
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
The volume of the sphere with radius(r) is,
Volume = (4/3)×π×r³
The volume of the sphere with radius (0.3r) is,
Volume = (4/3)×π×(0.3r)³
The difference in the volume between a sphere with radius r and a sphere with radius 0.3r is,
Difference = [(4/3)×π×r³] - [(4/3)×π×(0.3r)³]
= (4/3)πr³[1-0.027]
= (4/3)πr³(0.973)
= 4.0757r³ unit³
Hence, The difference in the volume between a sphere with radius r and a sphere with radius 0.3r is 4.0757r³ unit³.
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