in triangle ABC shown below, L is the midpoint of BC, M is the midpoint of AB, and N is the midpoint of AC. Find the perimeter of trapazoid BMNC.
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35
since m and n are the midpoints of ab and ac resistively
then ,bc=2mn=16
since m and l are the midpoints of ba and bc respectively
then, ac =2mn =10
then,nc =1/2 × 10 =5
similary, mb=6
then ,perimeter=nc+mb+mn+bc=5+6+8+16=35