The volume (in litres) of 2.75 g of fluorine gas at 35 °C and 4.55 atm is 0.402 L
How to determine the mole of fluorine gas
- Mass of F₂ = 2.75 g
- Molar mass of F₂ = 2 × 19 = 38 g/mol
- Mole of F₂ =?
Mole = mass / molar mass
Mole of F₂ = 2.75 / 38
Mole of F₂ = 0.0724 mole
How to determine the volume
- Temperature (T) = 35 °C = 35 + 273 = 308 K
- Pressure (P) = 4.55 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
- Number of mole (n) = 0.0724 mole
- Volume (V) =?
Using the ideal gas equation, the volume of the gas can be obtained as follow:
PV = nRT
Divide both side by P
V = nRT / P
V = ( 0.0724 × 0.0821 × 308) / 4.55
V = 0.402 L
Learn more about ideal gas equation:
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